A cubical block of side a is moving with velocity V on a horizontal smooth plane as shown in Figure. It hits a ridge at point O. The angular speed of the block after it hits O is

Options

A. `3v//4a`
B. `3v//2a`
C. `(sqrt3v)/(sqrt2a)`
D. zero

Explanation

`mc(a)/(2)=Iomega=[(ma^(2))/(6)+m((a)/(sqrt2))^(2)]omega`
`((ma^(2))/(6)+(ma^(2))/(2))omega=(2ma^(2))/(3)omega`
`omega=(3v)/(4a)`