A playground merry-go-round is at rest, pivoted about a frictionless axis. A child of mass `m` runs along a path tangential to the rim with speed `v` and jumps on to the merry-go-round. If `R` is the radius of the merry-go-round and `I` is its moment of inertia, then the angular velocity of the merry-go-round is

Options

A. `(mvR)/(mR^(2)+I)`
B. `(mvR)/(I)`
C. `(mR^(2))/(mvR)`
D. `(I)/(mvR)`

Explanation

`mvR=(I+mR^(2))omegaimpliesomega=(mvR)/(I+mR^(2))`