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A disc is rolling (without slipping) on ...

A disc is rolling (without slipping) on a horizontal surface. `C` is its center and `Q` and `P` are two points equidistant from `C`. Let `V_(P), V_(Q)` and `V_(C)` be the magnitude of velocities of points `P, Q` and `C` respectively, then
.

A

`v_(Q) gt v_(C) gt v_(P)`

B

`v_(Q) lt v_(C) lt v_(P)`

C

`v_(Q) = v_(P)`, `v_(C) = v_(P)`

D

`v_(Q) lt v_(C) gt v_(P)`

Text Solution

Verified by Experts


`v_(C)=v`
`P :`
`v_(P)=sqrt(v^(2)+(romega)^(2)+2xxvxxromega cos(90+theta))`
`Q :`
`v_(Q)=sqrt(v^(2)+(romega)^(2)+2xxvxxromega costheta)`
`v_(Q) gt v_(C) gt v_(P)`
OR
Assuming motion as the case of pure rotation about the point of contact
`v_(C)=Romega, v_(Q)=r_(2)omega, v_(P)=r_(1)omega`
`v_(Q) gt v_(C) gt v_(P)`
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