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A ball rolls without slipping. The radiu...

A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is `k`. If radius of the ball be `R`, then the fraction of total energy associated with its rotation will be.

A

`(k^(2))/(R^(2))`

B

`(k^(2))/(k^(2)+R^(2))`

C

`(R^(2))/(k^(2)+R^(2))`

D

`(k^(2)+R^(2))/(R^(2))`

Text Solution

Verified by Experts

`(K_(g))/(K)=((1)/(2)mv^(2)xx(k^(2))/(R^(2)))/((1)/(2)mv^(2)(1+(k^(2))/(R^(2))))=(k^(2))/(k^(2)+R^(2))`
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