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A body of mass m slides down an incline ...

A body of mass `m` slides down an incline and reaches the bottom with a velocity `v`. If the same mass were in the form of a ring which rolls down this incline, the velocity of the ring at the bottom would have been

A

`v`

B

`sqrt2 v`

C

`(1)/(sqrt2)v`

D

`sqrt((2)/(5)v)`

Text Solution

Verified by Experts

`v=sqrt(2gh)`
`v'=sqrt((2gh)/(1+k^(2)//R^(2)))=sqrt((2gh)/(1+1))=sqrt(gh)=(v)/(sqrt2)`
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