A thin uniform circular ring is rolling down an inclined plane of inclination `30^(@)` without slipping. Its linear acceleration along the inclined plane will be

Options

A. `g//2`
B. `g//3`
C. `g//4`
D. `2g//3`

Explanation

To find the linear acceleration of a thin uniform circular ring rolling down an inclined plane of inclination \(30^\circ\) without slipping, we can follow these steps:

### Step 1: Understand the Forces Acting on the Ring
When the ring is rolling down the incline, the gravitational force acting on it can be resolved into two components:
- The component along the incline: \(mg \sin \theta\)
- The component perpendicular to the incline: \(mg \cos \theta\)

### Step 2: Apply Newton's Second Law
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