A point particle of mass `0.1kg` is executing SHM of amplitude `0.1m`. When the particle passes through the mean position, its kinetic energy is `8xx10^-3J`. Obtain the equation of motion of this particle if the initial phase of oscillation is `45^@`.

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas related to Simple Harmonic Motion (SHM).

### Step 1: Identify the given data
- Mass of the particle, \( m = 0.1 \, \text{kg} \)
- Amplitude of SHM, \( A = 0.1 \, \text{m} \)
- Kinetic energy at mean position, \( KE = 8 \times 10^{-3} \, \text{J} \)
- Initial phase of oscillation, \( \phi = 45^\circ \)

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