A body makes angular simple harmonic motion of amplitude `pi//10rad` and time period `0.05s`. If the body is at a displacement `theta = pi//10 rad` at `t = 0`, write the equation giving angular displacement as a function of time.

Explanation

`theta_0=(pi)/(16)rad`, `T=0.05s`
Let `theta=theta_0sin(omegat+phi)`
At `t=0`, `theta=theta_0=(pi)/(10)`
`sin phi=1impliesphi=pi//2`
`theta=theta_0sin((2pi)/(T)t+(pi)/(2))=(pi)/(10)sin((2pi)/(0.05)t+pi/2)`
`theta=(pi)/(10)cos(40pit)`