A body of mass `5g` is executing SHM with amplitude `10cm`, its velocity is `100cm//s`. Its velocity will be `50cm//s` at a displacement from the mean position equal to

Options

A. `5cm`
B. `5sqrt3`
C. `10sqrt3cm`
D. `15sqrt3cm`

Answer

B

Explanation

`A=10cm`, `v_(max)=100cm//s`, `v=50cm//s`, `x=?`
`v_(max)=Aomegaimplies100=10omegaimpliesomega=10rad//s`
`v=omegasqrt(A^2-x^2)`
`50=10sqrt((10)^2-x^2)`
`x=5sqrt3cm`