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Two particles P and Q start from origin and execute simple harmonic motion along X-axis with same amplitude but with periods `3s` and `6s` respectively. The ratio of the velocities of P and Q when they meet is

A

`1:2`

B

`2:1`

C

`2:3`

D

`3:2`

Text Solution

Verified by Experts

The correct Answer is:
B

`x_p=asin((2pi)/(3))t`, `v_p=(dx_P)/(dt)=a*(2pi)/(3)cos((2pi)/(3))t`
`x_Q=asin((2pi)/(6))t`, `v_Q=(dx_Q)/(dt)=a*(2pi)/(6)cos((2pi)/(6))t`
`(2pi)/(3)t=(2pi)/(6)t+2piimpliest=6s`
`(v_P)/(v_Q)=(a*2pi//3)/(a*2pi//6)(cos[(2pi//3)xx6])/(cos[(2pi//6)xx6])=2/1`
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