The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement (amplitude `=a`) is

Options

A. `a/2`
B. `asqrt2`
C. `a/sqrt2`
D. `(asqrt2)/(3)`

Answer

C

Explanation

`K=U`
`1/2momega^2(a^2-x^2)=1/2momega^2x^2`
`a^2-x^2=x^2impliesx=+-a/sqrt2`