The angular velocity and amplitude of simple pendulum are `omega` and r respectively. At a displacement x from the mean position, if its kinetic energy is T and potential energy is U, find the ration of T to U.

Options

A. `X^2omega^2//(a^2-X^2omega^2)`
B. `X^2//(a^2-X^2)`
C. `(a^2-X^2omega^2)//X^2omega^2`
D. `(a^2-X^2)//X^2`

Answer

B

Explanation

`T/V=(1/2momega^2(a^2-X^2))/(1/2momega^2X^2)=(a^2-X^2)/(X^2)`