The time period of simple pendulum is T. If its length is increased by 2%, the new time period becomes

Options

A. `0.98T`
B. `1.02T`
C. `0.99T`
D. `1.01T`

Answer

D

Explanation

`T=2pisqrt(L/g)`, `T^'=2pisqrt((L(1+2//100)/(g))`
`T^'/T=(1+2//100)^(1//2)=1+1/2*(2)/(100)=1*01`
`T^'=1.01T`