A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle `theta` with the vertical

Options

A. `tan^-1((a)/(g))` in the forward direction
B. `tan^-1((a)/(g))` in the backward direction
C. `tan^-1((g)/(a))` in the backward direction
D. `tan^-1((g)/(a))` in the forward direction

Answer

B

Explanation

`tan theta=(ma)/(mg)=a/g`
`theta=tan^-1(a//g)`