A simple pendulum of length l is suspen...

A simple pendulum of length `l` is suspended from the celing of a cart which is sliding without friction on as inclined plane of inclination theta . What will be the time period of the pendulum?

`2pi1/g`

`2pisqrt((1)/(gcostheta))`

`2pisqrt((1)/(gsintheta))`

`2pisqrt((1)/(g tantheta))`

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The correct Answer is:

`T=2pisqrt((l)/(gcostheta))`

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