The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If it is a 2 second's pendulum on earth?

Options

A. `1/sqrt2s`
B. `2sqrt2s`
C. `2s`
D. `1/2s`

Answer

B

Explanation

`g=(GM_e)/(R_e^2)`, `g^'=(G*2M_e)/((2R_e)^2)=g/2`
`T=2pisqrt(L/g)`, `T^'=2pisqrt(L/g^')`
`T^'/T=sqrt(g/g^')=sqrt((g)/(g//2))=sqrt2`
`T^'=sqrt2T=2sqrt2s`