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When a body is suspended from two light ...

When a body is suspended from two light springs separately, the periods of vertical oscillations are `T_1` and `T_2`. When the same body is suspended from the two spring connected in series, the period will be

A

`T_1+T_2`

B

`sqrt(T_1T_2)`

C

`sqrt((T_1^2+T_2^2)/(2))`

D

`sqrt(T_1^2+T_2^2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`T=2pisqrt(m/k)impliesTprop(1)/(sqrtk)implieskprop1/T^2`
`k_1porp1/T_1^2`, `k_2prop1/T_2^2`, `k_(eq)prop1/T^2`
`1/k_(eq)=(1)/(k_1)+(1)/(k_2)`
`T^2=T_1^2+T_2^2impliesT=sqrt(T_1^2+T_2^2)`
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