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Two bodies (M) and (N) of equal masses a...

Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.

A

`k_1/k_2`

B

`k_2/k_1`

C

`sqrt(k_1/k_2)`

D

`sqrt(k_2/k_1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v_(max)=A_Momega_M=A_Nomega_N`
`A_M/A_N=omega_N/omega_M=sqrt((k_2lm)/(k_1lm))=sqrt(k_2/k_1)`
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