A massless spring, having force constant k, oscillates with frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass `2m` is suspended from one half. The frequency of oscillation will now be

Options

A. `n`
B. `n//2`
C. `n//sqrt2`
D. `2n`

Answer

A

Explanation

For a spring, spring constant x length of spring =constant
`n=sqrt(k//m)`
`kl=k^'*l/2impliesk^'=2k`
`n^'=sqrt((k^')/(2m))=sqrt((2k)/(2m))=sqrt(k//m)=n`