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Two particles A and B execute simple har...

Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will be

A

`pi//2`

B

`0`

C

`2pi//5`

D

`pi//4`

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To find the phase difference between two particles A and B executing simple harmonic motion (SHM) when particle A completes one oscillation, we can follow these steps: ### Step 1: Identify the periods of the two particles - Particle A has a period \( T_A = T \). - Particle B has a period \( T_B = \frac{5T}{4} \). ### Step 2: Calculate the angular frequencies (ω) of both particles - The angular frequency \( \omega \) is given by the formula: \[ \omega = \frac{2\pi}{T} \] - For particle A: \[ \omega_A = \frac{2\pi}{T} \] - For particle B: \[ \omega_B = \frac{2\pi}{T_B} = \frac{2\pi}{\frac{5T}{4}} = \frac{8\pi}{5T} \] ### Step 3: Determine the phase of each particle at time \( t \) - Since both particles start from the mean position, their phases at any time \( t \) can be expressed as: \[ \phi_A = \omega_A t = \frac{2\pi}{T} \cdot t \] \[ \phi_B = \omega_B t = \frac{8\pi}{5T} \cdot t \] ### Step 4: Calculate the phase difference (Δφ) at time \( t \) - The phase difference between the two particles at any time \( t \) is given by: \[ \Delta \phi = \phi_A - \phi_B \] - Substituting the expressions for \( \phi_A \) and \( \phi_B \): \[ \Delta \phi = \left(\frac{2\pi}{T} t\right) - \left(\frac{8\pi}{5T} t\right) \] - Factoring out \( t \): \[ \Delta \phi = t \left(\frac{2\pi}{T} - \frac{8\pi}{5T}\right) \] - Simplifying the expression: \[ \Delta \phi = t \left(\frac{2\pi \cdot 5 - 8\pi}{5T}\right) = t \left(\frac{10\pi - 8\pi}{5T}\right) = t \left(\frac{2\pi}{5T}\right) \] ### Step 5: Evaluate the phase difference when particle A completes one oscillation - Particle A completes one oscillation at \( t = T \): \[ \Delta \phi = T \left(\frac{2\pi}{5T}\right) = \frac{2\pi}{5} \] ### Conclusion The phase difference between particles A and B when particle A completes one oscillation is: \[ \Delta \phi = \frac{2\pi}{5} \]

To find the phase difference between two particles A and B executing simple harmonic motion (SHM) when particle A completes one oscillation, we can follow these steps: ### Step 1: Identify the periods of the two particles - Particle A has a period \( T_A = T \). - Particle B has a period \( T_B = \frac{5T}{4} \). ### Step 2: Calculate the angular frequencies (ω) of both particles - The angular frequency \( \omega \) is given by the formula: ...
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