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Two simple pandulum whose lengths are 10...

Two simple pandulum whose lengths are `100cm` and `121cm` are suspended side by side. Then bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum will two be in phase again. ?

A

`11`

B

`10`

C

`21`

D

`20`

Text Solution

Verified by Experts

The correct Answer is:
B

`T=2pisqrt((100)/(g))=10T`, `T_2=2pisqrt((121)/(g))=11T`
`((2pi)/(10T)-(2pi)/(11T))t=2piimpliest=110T`
Number of oscillations by longer pendulum
`=(t)/(11T)=(110T)/(11T)=10`
OR
`(n+1)T_1=nT_2`
`(n+1)(10T)=nxx11Timplies10n+10=11n`
`impliesn=10`
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