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The amplitude of vibration of a particle...

The amplitude of vibration of a particle is given by `a_m=(a_0)//(aomega^2-bomega+c)`, where `a_0`, a, b and c are positive. The condition for a single resonant frequency is

A

`b^2=4ac`

B

`b^2gt4ac`

C

`b^2=5ac`

D

`b^2=7ac`

Text Solution

Verified by Experts

The correct Answer is:
A
`aomega^2-bomega+c=0impliesomega=(b+-sqrt(b^2-4ac))/(2a)`
For single frequency `b^2=4ac`
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