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A flask is filled with mercury at temper...

A flask is filled with mercury at temperature `28^(@)C` . If the flask and the contents are heated to `48^(@)C` , the volume of mercury above the mark will be `(alpha_(glass=9xx10^(-6)//^(@)C` , `gamma_(Hg)=180xx10^(-6)//^(@)C)`

A

`0.15cm^(3)`

B

`0.25cm^(3)`

C

`0.3cm^(3)`

D

`0.5cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(DeltaV_(m)=Vgamma_(m)Deltatheta=50xx180xx10^(-6)xx(48-28)`
`=0.18cm^(3)`
`(Deltav)_(g)=V3.alphaDeltatheta=50xx3xx10^(-6)xx(48-28)`
`=0.027cm^(3)`
`(DeltaV)_(m)=(DeltaV)_(g)=0.180-0.027=0.027=0.153cm^(3)`
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