When a block of iron in mercury at 0^@C,...

When a block of iron in mercury at `0^@C,` fraction `K_1`of its volume is submerged, while at the temperature `60^@C,` a fraction `K_2` is seen to be submerged. If the coefficient of volume expansion of iron is `gamma_(Fe)` and that of mercury is `gamma_(Hg),` then the ratio `(K_1)//(K_2)` can be expressed as

`(1+60gamma_(Fe))/(1+60gamma_(Hg))`

`(1-60gamma_(Fe))/(1+60gamma_(Hg))`

`(1-60gamma_(Fe))/(1-60gamma_(Hg))`

`(1+60gamma_(Fe))/(1+60gamma_(Hg))`

Text Solution

Verified by Experts

The correct Answer is:

`W=p_(0)k_(1)V_(0)g=p_(60)k_(2)V_(60)g`
`(k_(1))/(k_(2))=(p_(60))/(p_(0))(V_(60))/(V_(0))`
`=[(p_(0)//(1+gamma_(Hg)xx60))/(p_(0))](V_(0)(1+gamma_(Fe)xx60))/(V_(0))`
`=(1+60gamma_(Fe))/(1+60hgamma_(Hg))`

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