If in a triangle `ABC, 3 sin A = 6 sin B=2sqrt3sin C`, then the angle A is

If in a triangle ABC,3sin A=6sin B=2sqrt(3)sin C then the value of /_A=

In Delta ABC " if " 3 sin A = 6 sin B = 2 sqrt3 sin C , " then " angle A =

In a triangle ABC,3sin A+4cos B=6 and 4sin B+3cos A=1 hold.Then the angle C equals (measured in degree)

In a right angled Delta ABC, sin^2 A+ sin^2 B+sin^2 C =

In a Delta ABC sin A sin B sin C<=(3sqrt(3))/(8)

In a Delta ABC sin Asin B sin C <= (3sqrt3)/8

In a Delta ABC sin Asin B sin C <= (3sqrt3)/8

in a Delta ABC,3sin A+4cos B=6 and 3cos A+4sin B=1 then angle C is

In a right angle triangle ABC, right angle is at B if tan A=sqrt3 then find the value of Sin A cos C + cos a sin c