`cos^2x<1/2`

int (sin^2 x - cos^2 x)/(sin^2 x cos^2 x) dx is equal to :

When the determinant |{:(cos2x,sin^(2)x,cos4x),(sin^(2)x,cos2x,cos^(2)x),(cos4x,cos^(2)x,cos2x):}| is expanded in powers of sin x , the constant term in than or equal to expression is

When the determinant |{:(cos2x,sin^(2)x,cos4x),(sin^(2)x,cos2x,cos^(2)x),(cos4x,cos^(2)x,cos2x):}| is expanded in powers of sin x , the constant term is equal to expression is

Simplify [{:(cos^(2)x,sin^(2)x),(sin^(2)x,cos^(2)x):}]+[{:(sin^(2)x,cos^(2)x),(cos^(2)x,sin^(2)x):}]

Solve: [[cos^(2)x, sin^(2)x],[sin^(2)x, cos^(2)x]]+[[sin^(2)x, cos^(2)x],[cos^(2)x, sin^(2)x]]

6tan^(2)x-2cos^(2)x=cos2x if cos2x=

" if "A=[[cos^(2)x,sin^(2)x],[-sin^(2)x,-cos^(2)x]]" and "B=[[sin^(2)x,cos^(2)x],[-cos^(2)x,-sin^(2)x]]" then find "A+B"