(y)(T)/(5)=10

Solve the equation.(t)/(5)=10

The equation of a wave is given by y=10sin((2pi)/(45)t+alpha) If the displacement is 5 cm at t=0 ,then the total phase at t=7.5 sec is

Simplify.(i) (25xx t^(-4))/(5^(3)xx10xx t^(-8))(t!=0)( ii) (3^(-5)xx10^(-5)xx125)/(5^(-7)xx6^(-5))

A wave pulse on a horizontal string is represented by the function y(x, t) = (5.0)/(1.0 + (x - 2t)^(2)) (CGS units) plot this function at t = 0 , 2.5 and 5.0 s .

A wave pulse on a horizontal string is represented by the function y(x, t) = (5.0)/(1.0 + (x - 2t)^(2)) (CGS units) plot this function at t = 0 , 2.5 and 5.0 s .

If x = 16, y = 10, z = 5 and t=-1, find the value of (x-y)(5sqrtx-y)+sqrt((x-y)(z-t)) .

The distance from the line x=2+t,y=1+t,z= -(1)/(2)-(1)/(2)t to the plane x+2y+6z=10 is (lambda)/(sqrt(mu)) . Then 5lambda-mu=