[1,-tan theta],[tan theta,1]

If f:[0,(pi)/(2))rarr R is defined as f(theta)=det[[1,tan theta,1-tan theta,1,tan theta-1,-tan theta,1]] Then,the range of f is

If f(theta) = |(1,tan theta,1),(- tan theta,1,tan theta),(-1,-tan theta,1)|, " then the set " {f(theta ) : 0 le theta le (pi)/(2)} is

If f(theta) = |(1,tan theta,1),(- tan theta,1,tan theta),(-1,-tan theta,1)|, " then the set " {f(theta ) : 0 le theta le (pi)/(2)} is

A function f:(0,pi //2) to R is defined as : f(theta )=|(1,tan theta ,1),(-tan theta ,1,tan theta ),(-1,-tan theta ,1)| then the range of f is -

(2cos^(2)theta-1)((1+tan theta)/(1-tan theta)+(1-tan theta)/(1+tan theta))=?

given that tan(theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tan theta_(1)*tan theta_(2)) find (theta_(1)+theta_(2)) when tan theta_(1)=(1)/(2),tan theta_(2)=(1)/(3)

Show that [[cos theta,-sin theta],[sin theta,cos theta]]=[[1,-tan(theta)/(2)],[tan(theta)/(2),1]][[1,tan(theta)/(2)],[-tan(theta)/(2),1]]^(-1)

prove that :(1-sin2 theta)/(1+sin2 theta)=((1-tan theta)/(1+tan theta))^(2)