`sqrt(16/36+1/4)`

Consider the following statements. s_(1):-6=2ixx3i=sqrt((-4))xxsqrt(-9)) s_(2):sqrt((-4))xxsqrt((-9))=sqrt((-4)xx(-9)) s_(3):sqrt((-4))xxsqrt((-9))=sqrt(36) s_(4):sqrt(36)=6 Of these statements, the incorrect one is

Prove that: cos36^(@)=(sqrt(5)+1)/(4)

Simplify the following by factor method: sqrt(36)+sqrt(4)

Evaluate lim_(xto0)(sqrt(x^2+1)-1)/(sqrt(x^2+16)-4)

Evaluate the limits : lim_( xto0) (sqrt(x^2+1)-1)/(sqrt(x^2+16)-4)

Find the value of :- (i) sqrt(4) (ii) sqrt(9) (iii) sqrt(16) (iv)sqrt(36)

Find the value of :- (i) sqrt(4) (ii) sqrt(9) (iii) sqrt(16) (iv)sqrt(36)

Find the value of :- (i) sqrt(4) (ii) sqrt(9) (iii) sqrt(16) (iv)sqrt(36)

Simplify: sqrt (-16) + 3 sqrt (-25) + sqrt (-36) + sqrt (-625)