Let `f(x) =(alphax)/(x+1)` Then the value of `alpha` for which `f(f(x) = x` is

Let f(x)=(alpha x)/(x+1) Then the value of alpha for which f(f(x)=x is

If f(x) =(alphax)/(x+1), x ne 1 , then the value of alpha for which f(f(x))=x is:

If f (x) =(alphax)/(x+1) (x ne -1), then the value of alpha for which f {f(x)}=x is-

Let f(x ) = ( alpha x^2 )/(x+1),x ne -1 the value of alpha for which f(a) =a , (a ne 0) is

Let f(x) = (alpha x^(2))/(x+1), x ne -1 . The value of alpha for which f(a) = a, (a ne 0) is

Let f(x)=(ax)/(x+1), x ne1 , then the value of 'a' for which f[f(x)]=x is

Let f(x) = (alpha x^(2))/(x + 1), x ne - 1 , The value of alpha for which f(a) = a , (a ne 0 ) is

Let f : R - {(alpha )/(6) } to R be defined by f (x) = ( 3x + 3)/(6x - alpha). Then the value of alpha for which (fof) (x) = x , for all x in R -{(alpha)/(6)}, is :

Let f(x)=(alphax)/(x+1),xne0 , then for what value of alpha is f[f(x)]=x ?

Let f(x)=(alphax)/(x+1),x!=-1. Then write the value of alpha satisfying f(f(x))=x for all x!=-1.