Consider a metal exposed to light of wavelength 600nm. The maximum energy of the electrons doubles when light of wavelength 400nm is used. Find the work function in eV.

Consider a metal exposed to light of wavelength 600 nm. The maximum energy of the electron doubles when light of wavelength 400 nm is used. Find the work function in eV.

Consider a metal exposed to light of wavelength 600nm.The maximum energy of the electron doubles when light of wavelength 400 nm is used .Find the work function in eV.

Consider a metal exposed to light of wavelength 600 nm. The maximum energy of the electron doubled when light of wavelength 400 nm is used. Find the work function in eV.

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

The surface of a metal is illuminated with light of wavelength 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. What is the work function of the metal ? [ hC=1240 eV*nm ]

When a metal surface is illuminated by a light of wavelength 400nm and 250 nm . The maximum velocites of the photo electrons ejected are v and 2v respectively. The work function of the metal is (h= Planck's constant e= Velocity of light in air

If a metal is exposed with light of wavelength lambda, the maximum kinetic energy produced is found to be 2 eV. When the same metal is exposed to a wavelength (lambda)/(5) the maximum kinetic energy was found to be 14 eV. Find the value of work function (in eV).