Assuming an electron is confined to a 1 nm wide region. Find the uncertainty in momentum using Heisenberg uncertainty principle.
`("Take h"=6.63xx10^(-34)Js)`

Assuming an electron is confined to a 1nm wide region. Find the uncertainty in momentum using Heisenberg Uncertainty principle. You can assume the uncertainty in position Deltax as 1nm. Assuming p=Deltap , find the energy of the electron in electron volts.

Assuming an electron is confined to a 1nm wide region,find the uncertainty in momentum using Heisenberg Uncertainty principle .You can assume the uncertainty in position Deltax as 1 nm.Assuming p~~Deltap , find th energy of the electron in electron volts.

Assuming an electron is confined to a 1nm wide region, find the wavelength in momentum using Heisenberg Uncertainty principal (Deltax Deltap~~h) . You can assume the uncertainty in position Deltax and 1nm . Assuming p~=Deltap , find the energy of the electron in electron volts.

Assuming an electron is confined to a 1nm wide region, find the wavelength in momentum using Heisenberg Uncetainity principal (Deltax Deltap~~h) . You can assume the uncertainity in position Deltax and 1nm. Assuming p~=Deltap , find the energy of the electron in electron volts.

If a proton and an electron are confined to the same region.then uncertainty in momentum ……..

Uncertainty in position of a 0.25 kg particle is 10^(-5) , uncertainty of velocity is (h=6.6xx10^(-34) Js)

The uncertainty in momentum of an electron is 1xx10^(-5) kgms^(-1) . The uncertainty in its position will be (h= 6.62xx10^(-34) Js)

An atom has mass of 0.2 kg and uncertainty in its velocity is 6.218× 10^(−6) m/s then uncertainty in position is (h=6.626× 10^(−34) Js)