An element "X" has `IP=1681` kJ/mole and `EA=-333` kJ/mole then its electronegativity is

An element X has IE and EA respectively 275 and 1450 kJ mol^(-1) . The electronegativity of element according to Pauling scale is

An element X has IE and EA respectively 275 and 1450 kJ mol^(-1) . The electronegativity of element according to Pauling scale is

If I and E are ionisation energy and electron affinity of an element in kJ "mole"^(-1) electronegativity is given as

triangleG^@ and triangleH^(@) for a reaction at 300K are -66.9 kJ/mole and 41.8 kJ/mole respectively. triangleG^(@) for the same reaction at 330K is

If DeltaH_(f)^(@) for H_(2)O_(2) and H_(2)O are -188 kJ/mole and -286 kJ/mole, what will be the enthalpy change of the reaction

The I_(1),I_(2),I_(3),I_(4) values of an element "M" are 120 kJ/mole, 600 kJ//"mole", 1000 kJ//"mole" and 8000 kJ//"mole" . Then the formula of its sulphate is

I_1 of an element X is 899 kJ "mole"^(-1) and that of another element Y is 801kJ mole-1. Then X and Y may be