[int(log x)/((1+log x)^(2))dx=],[[(A)(1)/(1+log x)+c," (B) "(x)/((1+log x)^(2))+c]" (c) "(x)/(1+log x)+cquad " (D) "(1)/((1+log x)^(2))+c]

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c

int(1+logx)/((1+xlogx)^(2))dx is equal to a) (1)/(1+xlog|x|)+C b) (1)/(1+log|x|)+C c) (-1)/(1+xlog|x|)+C d) log|(1)/(1+log|x|)|+C

If x^(y)=e^(x-y), then (dy)/(dx) is (1+x)/(1+log x)(b)(1-log x)/(1+log x)(c) not defined (d) (log x)/((1+log x)^(2))

int (dx)/((x+1)(x-2))=A log (x+1)+B log (x-2)+C , where

int (dx)/((x+1)(x-2))=A log (x+1)+B log (x-2)+C , where

int(log|x|)/(x sqrt(1+log|x|))dx=...+c .

int (log x)/(x^(2))dx is equal to a) (log x)/(x) + (1)/(x^(2)) +C b) -(log x)/(x) + (2)/(x) + C c) -(log x)/(x) - (1)/(2x) + C d) -(log x)/(x) - (1)/(x) + C

intx^(3) log x dx is equal to A) (x^(4) log x )/( 4) + C B) (x^(4))/( 8) ( log x - ( 4)/( x^(2)))+C C) (x^(4))/( 16) ( 4 log x -1) +C D) (x^(4))/( 16) ( 4 log x +1) + C

int_(log(1/2))^(log2) log(x+sqrt(x^2+1))dx= (A) 2log2 (B) 1-log2 (C) 1+log2 (D) 0

int x^x (1+ log x) dx =............. A) (1/2) (1+log x)^2 +c B) x^(x) + c C) x^x log x + c D) x^2 + c