[" The mini mum value at "],[qquad f(x)=|x-1|+|x-2|+|x-3|" is aqual to "]

The minimum value of f(x)=2x^2+3x+1 is

The smallest value of the function f(x)=3|x+1|+|x|+3|x-1|+2|x-3|

If f(x)=|x-1|+|x-3| ,then value of f'(2) is equal to

Maximum value of f(x)= (x-2)^(2) . (x-3) +1 is

f(x)=((x-2)(x-1))/(x-3), forall xgt3 . The minimum value of f(x) is equal to

f(x)=((x-2)(x-1))/(x-3), forall xgt3 . The minimum value of f(x) is equal to

f(x)=((x-2)(x-1))/(x-3), forall xgt3 . The minimum value of f(x) is equal to

If f(x)=|x-1|+|x-2|-|x-3|, then (a) maximum value of f(x) is 3 if x in[2,3] (b) maximum value of f(x) is -3 if x in[1,3] (c) maximum value of f(x) is -3 if x in[1,2] (d) maximum value of f(x) is 3 if x in[1,3]

If f (x) = |x|+|x-1|, find the value of : f(1/3) .

The value of 3 f(x ) - 2 f(1/x)=x then f^(1)(2) =