[" If "|x-1|>5" then "],[" a) "x in(-4,6)," b) "x in[-4,6]],[" c) "x in(-oo,-4)uu(6,oo)," d) "x in(-oo,-4)uu[6,oo)]

If |x-1|>5, then x in(-4,6) b.x in[-4,6] c.x in(-oo,-4)uu(6,oo) d.x in(-oo,-4)uu[6,oo)

If |x+2|lt=9 then x in (-7, 11) b. x in [-11 ,7] c. x in (-oo,7)uu(11 ,oo) d. x in (-oo,-7)uu[11 ,oo)

If |x+2|lt=9 then x in (-7, 11) b. x in [-11 ,7] c. x in (-oo,7)uu(11 ,oo) d. x in (-oo,-7)uu[11 ,oo)

If |x-2| (A) x in R , (B) x in[0,oo)] , (C) x in(-oo,(4-sqrt(2))/(2)]uu[(5)/(2),oo), (D) x in(-oo,(4-sqrt(2))/(2)]uu[(5+sqrt(3))/(2),oo]

If |x+3|geq10 , then x in (-13 ,\ 7] b. x in (-oo,-13)uu(7,oo) c. x in (-13 ,7) d. x in (-oo,\ -13]uu[7,oo)

If |x+3|>=10, then x in(-13,7] b.x in(-oo,-13)uu(7,oo) c.x in(-13,7) d.x in(-oo,-13]uu[7,oo)

Solution set of the inequation, (x^2-5x+6)/(x^2+x+1)<0 is x in (-oo,2) (b) x in (2,3) x in (-oo,2)uu(3,oo) (d) x in (3,oo)

If x and a are real numbers such that a>0 and |x|>a, then x in(-a,oo) b.x in[-oo,a) c.x in(-a,a) d.x in(-oo,-a)uu(a,oo)

Solution set of the inequation,(x^(2)-5x+6)/(x^(2)+x+1)<0 is x in(-oo,2) (b) x in(2,3)x in(-oo,2)uu(3,oo)( d) x in(3,oo)

The quadratic equation (a+3)x^(2)-ax+1=0 has two distinct real solutions a) for a in(-2,6) b) for a in(-oo,0)uu(7,oo) c) for a in(-oo,-2)uu(6,oo)-{-3} d) for a in(0,7)