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" (ii) "((3)/(5))^(4)((8)/(5))^(-12)((32...

" (ii) "((3)/(5))^(4)((8)/(5))^(-12)((32)/(5))^(6)

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Simplify: ((3)/(5))^(4)((8)/(5))^(-12)((32)/(5))^(6)-:((3^(4)xx5^(2))/(2^(6)))

3. Simplify the following: (3/5)^4(8/5)^(-12)(32/5)^6

The sum and product of the slopes of the tangents to the hyperbola (x^(2))/(4)-(y^(2))/(2)=1 drawn from the point (3,-2) are (A)-(12)/(5),(6)/(5)(B)(12)/(5),(6)/(5)(C)(11)/(4),(7)/(5)(D)-(12)/(5),(8)/(5)

Simplify: (3/4)^4(8/5)^-12(32/5)^6

Simplify: (3/4)^4 (8/5)^(-3/2) (32/5)^6

Simplify: 4((5)/(6))-2((3)/(8))+3((7)/(12))

Fill in the blanks substituting proper numbers: (i) (5)/(12)=(……….)/(6) (ii) (1)/(8)=(4)/(…….) (iii) (a)/(5)=(b)/(3)=(3a+5b)/(.........)

Simplify : a. 15^(7)-:5^(3) b. ((5^(4))^(3)xx2^(12))/(3^(12)) c. ((4^(3))^(2)xx5^(6))/(10^(6)) d. (2xx3^(4)xx2^(5))/(9xx4^(2)) e. (2^(2)xx3^(4)xx16)/(3^(2)xx32) f. (4^(5)xxa^(8)xxb^(16))/(4^(4)xxa^(7)xxb^(4))

If 2 (3)/(4) - (5)/(8) + (-5)/(12) + 1 (1)/(6) = k, then find k.

Simpilfy: 5(3)/(4)- 4 (5)/(12)+3(1)/(6)