[" Question "54],[qquad (cos^(-1)x)=sin(cot^(-1)(1)/(2))" then "x=]

tan (cos ^(-1) x) = sin (cot ^(-1) ""(1)/(2))

If: cos(tan^(-1)x)=sin (cot^(-1).(3)/(4)), then : x =

Slove: tan(cos^-1x)=sin(cot^-1""1/2)

cos [ tan^(-1){sin (cot^(-1)x)}] =

cos[tan^(-1) {sin(cot^(-1) x)}] =

sin {cot^(-1)[tan (cos^(-1)x)]=

Solve the following equation for x:cos(tan^(-1)x)=sin((cot^(-1)3)/(4))tan(cos^(-1)x)=sin((cot^(-1)1)/(2))

If sin (cot^(-1)(1-x))=cos(tan^(-1)(-x)) , then x is

f(x)=cos(2tan^-1(sin(cot^-1sqrt((1-x)/x)))) then