A body of mass `2kg` is moving with a velocity of `vecu=3hati+4hatj m//s`.A steady force `vecF=hati-2hatj N` begins to act on it. After four second, the body will be moving along.

A body of mass 5 kg starts from the origin with an initial velocity vecu=30hati+40hatjms^(-1) . If a constant force vecF=-(hati+5hatj)N acts on the body, the time in which the y-component of the velocity becomes zero is

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A body of mass 5 kg is moving with velocity of v=(2hati+6hatj)ms^(-1) at t=0s. After time t=2s, velocity of body is (10 hati+6 hatj) , then change in momentum to body is