(a) If gravitational field is given by `vecE=-2xhati-3y^(2)hatj`. If gravitational potential is zero at `(0,0)`, find potential at `(1,2)`
(b) If gravitational potential is `V=x^(2)Y`, find gravitational field at `(1,2)`.

Explanation

To solve the given problem step by step, we will break it down into two parts as per the question.

### Part (a): Finding the Potential at (1, 2)

1. **Understanding the Gravitational Field**:
The gravitational field is given by:
\[
\vec{E} = -2x \hat{i} - 3y^2 \hat{j}
...