As satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth\'s surface. Find a). its speed in the orbit b). its kinetic energy. c). The potential energy of the earth satelilte system and d). its time period. Mass of the earth `=6xx10^24kg`.

Explanation

`m=1000 kg,h=2000 km,M=6xx10^(24)kg`
(a) `v_(0)=sqrt((GM_(e))/(R_(e)+h))=sqrt((6.67xx10^(-11)xx6xx10^(24))/((6400+2000)xx10^(3)))`
`=6.9xx10^(3)m//s`
(b) `K=1/2mv_(0)^(2)=1/2xx1000(6.9xx10^(3))^(2)=2.38xx10^(10)J`
(c) `U=-2K=-4.76xx10^(10)J`
(d) `T=(2pi(R_(e)+h))/(v_(0))=(2pixx8400xx10^(3))/(6.9xx10^(3))=72365=2.01 hr`