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The weight of an object in the coal mine...

The weight of an object in the coal mine, sea level and at the top of the mountain are `W_(1),W_(2)` and `W_(3)` respectively, then

A

`W_(2) gt W_(1) gt W_(3)`

B

`W_(1)=W_(2)=W_(3)`

C

`W_(1) lt W_(2) lt W_(3)`

D

`W_(1) gt W_(2) gt W_(3)`

Text Solution

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The correct Answer is:
To solve the problem regarding the weights of an object at different locations (coal mine, sea level, and top of a mountain), we will analyze how the gravitational force (weight) changes based on the distance from the center of the Earth. ### Step-by-Step Solution: 1. **Understanding Weight**: The weight of an object is given by the formula: \[ W = m \cdot g \] where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity. 2. **Weight at Sea Level (W2)**: At sea level, the weight is simply: \[ W_2 = m \cdot g \] Here, \( g \) is the standard acceleration due to gravity at sea level. 3. **Weight in the Coal Mine (W1)**: When we go down into a coal mine, we are moving below the surface of the Earth. The variation of gravitational acceleration at a depth \( d \) is given by: \[ g' = g \left(1 - \frac{d}{R}\right) \] where \( R \) is the radius of the Earth. Thus, the weight at this depth is: \[ W_1 = m \cdot g' = m \cdot g \left(1 - \frac{d}{R}\right) \] 4. **Weight at the Top of the Mountain (W3)**: When we go to a height \( h \) above sea level, the variation of gravitational acceleration is given by: \[ g' = g \left(1 - \frac{2h}{R}\right) \] Therefore, the weight at this height is: \[ W_3 = m \cdot g' = m \cdot g \left(1 - \frac{2h}{R}\right) \] 5. **Comparing Weights**: Now we need to compare \( W_1 \), \( W_2 \), and \( W_3 \): - At sea level, \( W_2 = m \cdot g \). - In the coal mine, \( W_1 = m \cdot g \left(1 - \frac{d}{R}\right) \) which is less than \( W_2 \) since \( d/R \) is positive. - At the top of the mountain, \( W_3 = m \cdot g \left(1 - \frac{2h}{R}\right) \) which is also less than \( W_2 \) and generally less than \( W_1 \) if \( h \) is sufficiently large. 6. **Conclusion**: From the analysis, we can conclude: \[ W_2 > W_1 > W_3 \] Therefore, the relationship between the weights is: \[ W_2 > W_1 > W_3 \] ### Final Answer: The correct relationship is \( W_2 > W_1 > W_3 \). ---

To solve the problem regarding the weights of an object at different locations (coal mine, sea level, and top of a mountain), we will analyze how the gravitational force (weight) changes based on the distance from the center of the Earth. ### Step-by-Step Solution: 1. **Understanding Weight**: The weight of an object is given by the formula: \[ W = m \cdot g ...
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CP SINGH-GRAVITATION-EXERCISE
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  2. Let the acceleration due to gravity be g(1) at a height h above the ea...

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  3. The weight of an object in the coal mine, sea level and at the top of ...

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  4. Suppose the earth increases its speed of rotation . At what new time p...

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  11. A spherically symmetric gravitational system of particles has a mass d...

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  16. Figure shows the motion of a planet around the Sun S in an elliptical ...

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  17. The earth E moves in an elliptical orbit with the sun S at one of the ...

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