In a satellite if the time of revolution is `T`, then kinetic energy is proportional to

Options

A. `1/T`
B. `1/(T^(2))`
C. `1/(T^(3))`
D. `T^(2//3)`

Answer

B

Explanation

`K=1/2mv^(2)=1/2m omega^(2) R^(2)=1/2m((2pi)/T)^(2) R^(2)`
`=(2pi^(2)mR^(2))/(T^(2))`
`K prop 1/(T^(2))`