The temperature at which the speed of sound in air becomes double of its value at `0^(@)C` is

Options

A. `1092^(@) C`
B. `819 K`
C. `819^(@) C`
D. `546^(@) C`

Answer

C

Explanation

`v prop sqrt(T)`
`(v_(2))/(v_(1)) = sqrt(T_(2)/T_(1)) = sqrt(T_(2)/273)`
`T_(2) = 4 xx 273 = 1092 K`
`= 1092 - 273 = 819^(@) C`