A stone is dropped into a well. If the depth of water below the top be `h` and velocity of sound is `v` then the splash in water is heard after `T` sec. Then:

Options

A. `T = sqrt(((2 h)/(g))) = (h)/(v)`
B. `T = 2 sqrt(((2 h)/(g)))`
C. `T = (2 h)/(v)`
D. `T = sqrt(((2 h)/(g))) xx (h)/(v)`

Answer

A

Explanation

`h = (1)/(2)g t_(1)^(2) rArr t_(1) = sqrt((2h)/(g))`
`t_(2) = (h)/(v)`
`T = t_(1) + t_(2) = sqrt((2h)/(g)) + (h)/(v)`