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Two loudspeakers L1 and L2 driven by a c...


Two loudspeakers `L_1` and `L_2` driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at D records a series of maxima and minima. If the speed of sound is `330ms^-1` then the frequency at which the first maximum is observed is

A

`165 Hz`

B

`330 Hz`

C

`496 Hz`

D

`660 Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta x = L_(2)D - L_(1)D = sqrt((99)^(2) + (40)^(2)) - 40`
`= 41 - 40 = 1 m`
For maximum intensity
`Delta x = n lambda = n(v)/(f)`
`f = (n v)/(Delta x) = (n xx 330)/(1) = 330 n`
`n = 1, f = 330 Hz`
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