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Each of the two strings of length 51.6 c...

Each of the two strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is same and equal to `1 g//m`. When both the strings vibrate simultaneously, the number of beats is

A

`5`

B

`7`

C

`8`

D

`3`

Text Solution

Verified by Experts

The correct Answer is:
B
`(1)/(2 xx 0.491)sqrt((20)/(1xx10^(-3))) ~ (1)/(2 xx 0.516)sqrt((20)/(1 xx 10^(-3)))`
`=` Beat frequency
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