For a certain organ pipe, three successive resonance frequencies are observer at `425`, `595` and `765 H_(Z)` respectively. Taking the speed of sound in air to be `340 m//s`, (a) explain whether the pipe is closed at one or open at boyh ends. (b) determine the fundamental frequency and length of the pipe.

Options

A. closed pipe of length `1 m`
B. closed pipe of length `2 m`
C. open pipe of length `1 m`
D. open pipe of length `2 m`

Answer

A

Explanation

The different in successive frequencies of pipe
(Closed or open) `=(v)/(2 l)`
`(v)/(2 l) = 595-425 = 170`
`(340)/(2l) = 170 rArr l = 1 m`
Ratio of frequencies
`425:595:765: = 5:7:9` i.e odd numbers
i.e. closed pipe