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For a resonance tube, the air columns fo...

For a resonance tube, the air columns for the first and the second resonance differ in length by `31.5 cm`. The wavelength of the wave is

A

`15.75 cm`

B

`31.5 cm`

C

`63.0 cm`

D

`126.0 cm`

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To find the wavelength of the wave in the resonance tube, we can follow these steps: ### Step 1: Understand the relationship between the lengths of the air columns and the wavelength. In a resonance tube, the lengths of the air columns at the first and second resonance are related to the wavelength of the sound wave. The first resonance occurs at a length of \( \frac{\lambda}{4} \) and the second resonance occurs at a length of \( \frac{3\lambda}{4} \). ### Step 2: Set up the equation for the difference in lengths. Given that the difference in lengths of the air columns for the first and second resonance is \( 31.5 \, \text{cm} \), we can express this mathematically: \[ \frac{3\lambda}{4} - \frac{\lambda}{4} = 31.5 \, \text{cm} \] ### Step 3: Simplify the equation. Now, simplify the left side of the equation: \[ \frac{3\lambda}{4} - \frac{\lambda}{4} = \frac{2\lambda}{4} = \frac{\lambda}{2} \] So, we have: \[ \frac{\lambda}{2} = 31.5 \, \text{cm} \] ### Step 4: Solve for the wavelength \( \lambda \). To find \( \lambda \), multiply both sides of the equation by 2: \[ \lambda = 2 \times 31.5 \, \text{cm} = 63 \, \text{cm} \] ### Conclusion: The wavelength of the wave is \( \lambda = 63 \, \text{cm} \). ---

To find the wavelength of the wave in the resonance tube, we can follow these steps: ### Step 1: Understand the relationship between the lengths of the air columns and the wavelength. In a resonance tube, the lengths of the air columns at the first and second resonance are related to the wavelength of the sound wave. The first resonance occurs at a length of \( \frac{\lambda}{4} \) and the second resonance occurs at a length of \( \frac{3\lambda}{4} \). ### Step 2: Set up the equation for the difference in lengths. Given that the difference in lengths of the air columns for the first and second resonance is \( 31.5 \, \text{cm} \), we can express this mathematically: \[ ...
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CP SINGH-SOUND WAVES-Exercises
  1. In an experiment, it was found that a tuning fork and sonometer wire g...

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  2. Sound waves of frequency 600 H(Z) fall normally on perfectly reflectin...

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  3. For a resonance tube, the air columns for the first and the second res...

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  4. In a resonance tube, using a tuning fork of frequency 325 Hz, the firs...

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  5. In previous problem, end correction is

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  6. An air column, closed at one end and open at the other end, resonates ...

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  7. A long glass tube is held vertically in water. A tuning fork is struck...

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  8. A glass tube of 1.0 m length is filled with water. The water can be dr...

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  9. A tuning fork of frequency 340 H(Z) is sounded above an organ pipe of ...

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  10. On producing the waves of frequency 1000 Hz in a kundt's tube the tota...

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  11. If in an experimental determination of the velocity of sound using a K...

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  12. The change in frequency due to Doppler effect does not depend on

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  13. The engine of a train sound a whistle at frequency v, the frequency he...

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  14. A small source of sound moves on a circle as shown in figure and an ob...

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  15. A source of sound moves towards an observe.

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  16. A listener is at rest with respect to the source of sound. A wind star...

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  17. A tuning fork of frequency 90 Hz is sounded and moved towards an obser...

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  18. A source and a listener are both moving towards each other with speed ...

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  19. A source of sound is travelling towards a stationary observer. The fre...

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  20. The difference between the apparent frequency of a sound of soun as pe...

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