In a resonance tube, using a tuning fork...

In a resonance tube, using a tuning fork of frequency `325 Hz`, the first two resonance lengths are observed at `25.4 cm` and `77.4 cm`. The speed of sound in air is

`318 m//s`

`338 m//s`

`358 m//s`

`378 m//s`

Text Solution

Verified by Experts

The correct Answer is:

`v = 2 f((l_(2) - l_(1))`
`= 2 xx 325 (77.4 - 25.4) xx 10^(-2)`
`= 338 m//s`

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